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window: destroy the 2nd shm buffer, if both released

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Handle the case when we the compositor somehow migrates from requiring
double buffering into working on single buffering, so we release the
extra shm buffer.

Currently, I do not think this can happen in practice, but in the future
it may happen with sub-surfaces.

Signed-off-by: Pekka Paalanen <ppaalanen@gmail.com>
This commit is contained in:
Pekka Paalanen 2013-02-13 16:17:12 +02:00 • committed by Kristian Høgsberg
parent 33a68eaaf4
commit 550d66bcb1
1 changed files with 12 additions and 10 deletions
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22
clients/window.c
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@ -807,6 +807,8 @@ shm_surface_leaf_release(struct shm_surface_leaf *leaf)
if (leaf->resize_pool)
shm_pool_destroy(leaf->resize_pool);
memset(leaf, 0, sizeof *leaf);
}
struct shm_surface {
@ -829,17 +831,17 @@ to_shm_surface(struct toysurface *base)
static void
shm_surface_buffer_release(void *data, struct wl_buffer *buffer)
{
struct shm_surface_leaf *leaf = data;
struct shm_surface *surface = data;
leaf->busy = 0;
if (surface->leaf[0].data->buffer == buffer)
surface->leaf[0].busy = 0;
else if (surface->leaf[1].data->buffer == buffer)
surface->leaf[1].busy = 0;
else
assert(0 && "shm_surface_buffer_release: unknown buffer");
/* If both leaves are now free, we should call
* shm_surface_leaf_release(shm_surface::leaf[1]).
* However, none of Weston's backends switch dynamically
* between early buffer release and requiring double-buffering,
* so if both leaves are free, we never used the second
* leaf to begin with.
*/
if (!surface->leaf[0].busy && !surface->leaf[1].busy)
shm_surface_leaf_release(&surface->leaf[1]);
}
static const struct wl_buffer_listener shm_surface_buffer_listener = {
@ -908,7 +910,7 @@ shm_surface_prepare(struct toysurface *base, int dx, int dy,
leaf->resize_pool,
&leaf->data);
wl_buffer_add_listener(leaf->data->buffer,
&shm_surface_buffer_listener, leaf);
&shm_surface_buffer_listener, surface);
out:
surface->current = leaf;