These transformations are inexact because section 4.7.1 (Range and
Precision) says:
Operations and built-in functions that operate on a NaN are not
required to return a NaN as the result.
The fmin or fmax might not return NaN in cases where the original
expression would be required to return NaN.
Signed-off-by: Ian Romanick <ian.d.romanick@intel.com>
Reviewed-by: Jason Ekstrand <jason@jlekstrand.net>
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