Fix typo in configure message for gcc -fvisibility=hidden

Need to use $CC for a shell variable, not $(CC) for a make variable
which the shell interprets as running the command "CC".

Signed-off-by: Alan Coopersmith <alan.coopersmith@sun.com>
This commit is contained in:
Alan Coopersmith 2010-01-21 16:42:58 -08:00
parent d65d5d2993
commit f8107a45ce

View file

@ -100,7 +100,7 @@ if test "x$GCC" = xyes; then
# Enable -fvisibility=hidden if using a gcc that supports it
save_CFLAGS="$CFLAGS"
AC_MSG_CHECKING([whether $(CC) supports -fvisibility=hidden])
AC_MSG_CHECKING([whether $CC supports -fvisibility=hidden])
CFLAGS="$CFLAGS -fvisibility=hidden"
AC_LINK_IFELSE([AC_LANG_PROGRAM()], AC_MSG_RESULT([yes]),
[CFLAGS="$save_CFLAGS" ; AC_MSG_RESULT([no])]);