ra: cleanup the public API

Previously, there were 3 entrypoints into parts of the actual allocator,
and an API called ra_allocate_no_spills() that called all 3. Nobody
would ever want to call any of the 3 entrypoints by themselves, so
everybody just used ra_allocate_no_spills(). So just make them static
functions, and while we're at it rename ra_allocate_no_spills() to
ra_allocate() since there's no equivalent "with spills," because the
backend is supposed to handle spilling.

Signed-off-by: Connor Abbott <connor.abbott@intel.com>
Reviewed-by: Eric Anholt <eric@anholt.net>
Reviewed-by: Kenneth Graunke <kenneth@whitecape.org>
This commit is contained in:
Connor Abbott 2014-07-31 18:57:20 -07:00 committed by Kenneth Graunke
parent d72d67832b
commit 9a0b52e7c1
5 changed files with 10 additions and 13 deletions

View file

@ -617,7 +617,7 @@ static void do_advanced_regalloc(struct regalloc_state * s)
input_node++;
}
if (!ra_allocate_no_spills(graph)) {
if (!ra_allocate(graph)) {
rc_error(s->C, "Ran out of hardware temporaries\n");
return;
}

View file

@ -486,7 +486,7 @@ fs_visitor::assign_regs(bool allow_spilling)
}
}
if (!ra_allocate_no_spills(g)) {
if (!ra_allocate(g)) {
/* Failed to allocate registers. Spill a reg, and the caller will
* loop back into here to try again.
*/

View file

@ -207,7 +207,7 @@ vec4_visitor::reg_allocate()
setup_payload_interference(g, first_payload_node, node_count);
if (!ra_allocate_no_spills(g)) {
if (!ra_allocate(g)) {
/* Failed to allocate registers. Spill a reg, and the caller will
* loop back into here to try again.
*/

View file

@ -440,7 +440,7 @@ pq_test(struct ra_graph *g, unsigned int n)
* means that either spilling will be required, or optimistic coloring
* should be applied.
*/
bool
static bool
ra_simplify(struct ra_graph *g)
{
bool progress = true;
@ -477,7 +477,7 @@ ra_simplify(struct ra_graph *g)
* If all nodes were trivially colorable, then this must succeed. If
* not (optimistic coloring), then it may return false;
*/
bool
static bool
ra_select(struct ra_graph *g)
{
int i;
@ -530,7 +530,7 @@ ra_select(struct ra_graph *g)
* locally-colorable and the rest of the register allocation
* will succeed.
*/
void
static void
ra_optimistic_color(struct ra_graph *g)
{
unsigned int i;
@ -547,7 +547,7 @@ ra_optimistic_color(struct ra_graph *g)
}
bool
ra_allocate_no_spills(struct ra_graph *g)
ra_allocate(struct ra_graph *g)
{
if (!ra_simplify(g)) {
ra_optimistic_color(g);
@ -618,11 +618,11 @@ ra_get_best_spill_node(struct ra_graph *g)
/* For any registers not in the stack to be colored, consider them for
* spilling. This will mostly collect nodes that were being optimistally
* colored as part of ra_allocate_no_spills() if we didn't successfully
* colored as part of ra_allocate() if we didn't successfully
* optimistically color.
*
* It also includes nodes not trivially colorable by ra_simplify() if it
* was used directly instead of as part of ra_allocate_no_spills().
* was used directly instead of as part of ra_allocate().
*/
for (n = 0; n < g->count; n++) {
float cost = g->nodes[n].spill_cost;

View file

@ -66,10 +66,7 @@ void ra_add_node_interference(struct ra_graph *g,
/** @} */
/** @{ Graph-coloring register allocation */
bool ra_simplify(struct ra_graph *g);
void ra_optimistic_color(struct ra_graph *g);
bool ra_select(struct ra_graph *g);
bool ra_allocate_no_spills(struct ra_graph *g);
bool ra_allocate(struct ra_graph *g);
unsigned int ra_get_node_reg(struct ra_graph *g, unsigned int n);
void ra_set_node_reg(struct ra_graph * g, unsigned int n, unsigned int reg);