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util/vma: Add a function to allocate a particular address range
This new function lets you request to remove a specific address range from the allocator. It returns true on success and leaves the allocator unmodified and returns false on failure. It doesn't need to return an offset because, if it succeeds, the offset passed in is the allocated offset. Reviewed-by: Ivan Briano <ivan.briano@intel.com> Reviewed-by: Lionel Landwerlin <lionel.g.landwerlin@intel.com>
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2 changed files with 41 additions and 0 deletions
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@ -170,6 +170,44 @@ util_vma_heap_alloc(struct util_vma_heap *heap,
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return 0;
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}
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bool
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util_vma_heap_alloc_addr(struct util_vma_heap *heap,
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uint64_t offset, uint64_t size)
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{
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/* An offset of 0 is reserved for allocation failure. It is not a valid
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* address and cannot be allocated.
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*/
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assert(offset > 0);
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/* Allocating something with a size of 0 is also not valid. */
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assert(size > 0);
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/* It's possible for offset + size to wrap around if we touch the top of
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* the 64-bit address space, but we cannot go any higher than 2^64.
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*/
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assert(offset + size == 0 || offset + size > offset);
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/* Find the hole if one exists. */
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util_vma_foreach_hole_safe(hole, heap) {
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if (hole->offset > offset)
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continue;
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/* Holes are ordered high-to-low so the first hole we find with
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* hole->offset <= is our hole. If it's not big enough to contain the
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* requested range, then the allocation fails.
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*/
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assert(hole->offset <= offset);
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if (hole->size < offset - hole->offset + size)
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return false;
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util_vma_hole_alloc(hole, offset, size);
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return true;
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}
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/* We didn't find a suitable hole */
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return false;
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}
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void
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util_vma_heap_free(struct util_vma_heap *heap,
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uint64_t offset, uint64_t size)
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@ -43,6 +43,9 @@ void util_vma_heap_finish(struct util_vma_heap *heap);
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uint64_t util_vma_heap_alloc(struct util_vma_heap *heap,
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uint64_t size, uint64_t alignment);
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bool util_vma_heap_alloc_addr(struct util_vma_heap *heap,
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uint64_t addr, uint64_t size);
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void util_vma_heap_free(struct util_vma_heap *heap,
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uint64_t offset, uint64_t size);
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