panfrost: Add a tiled 16x16 layout unit test

To exercise the layout code introduced in this series.

Signed-off-by: Alyssa Rosenzweig <alyssa@collabora.com>
Part-of: <https://gitlab.freedesktop.org/mesa/mesa/-/merge_requests/16697>
This commit is contained in:
Alyssa Rosenzweig 2022-05-04 11:16:48 -04:00 committed by Marge Bot
parent d11945cd85
commit 65ba39f84c

View file

@ -390,3 +390,42 @@ TEST(AFBCLayout, Linear3D)
EXPECT_EQ(l.slices[0].surface_stride, 2048); /* XXX: Not meaningful? */
EXPECT_EQ(l.slices[0].size, 32768); /* XXX: Not used by anything and wrong */
}
TEST(AFBCLayout, Tiled16x16)
{
uint64_t modifier = DRM_FORMAT_MOD_ARM_AFBC(AFBC_FORMAT_MOD_BLOCK_SIZE_16x16 |
AFBC_FORMAT_MOD_TILED |
AFBC_FORMAT_MOD_SPARSE);
struct pan_image_layout l = {
.modifier = modifier,
.format = PIPE_FORMAT_R8G8B8A8_UNORM,
.width = 917,
.height = 417,
.depth = 1,
.nr_samples = 1,
.dim = MALI_TEXTURE_DIMENSION_2D,
.nr_slices = 1
};
ASSERT_TRUE(pan_image_layout_init(&l, NULL));
/* The image is 917x417. Superblocks are 16x16, so there are 58x27
* superblocks. Superblocks are grouped into 8x8 tiles, so there are 8x4
* tiles of superblocks. So the row stride is 16 * 8 * 8 * 8 = 8192 bytes.
* There are 4 tiles vertically, so the header is 8192 * 4 = 32768 bytes.
* This is already 4096-byte aligned.
*
* Each tile of superblock contains 128x128 pixels and each pixel is 4 bytes,
* so tiles are 65536 bytes, meaning the payload is 8 * 4 * 65536 = 2097152
* bytes.
*
* In total, the AFBC surface is 32768 + 2097152 = 2129920 bytes.
*/
EXPECT_EQ(l.slices[0].offset, 0);
EXPECT_EQ(l.slices[0].row_stride, 8192);
EXPECT_EQ(l.slices[0].afbc.header_size, 32768);
EXPECT_EQ(l.slices[0].afbc.body_size, 2097152);
EXPECT_EQ(l.slices[0].surface_stride, 2129920);
EXPECT_EQ(l.slices[0].size, 2129920);
}