r600: double multiply can handle only one multiply at a time

It seems clear that trying to multiply two pairs of doubles would result
in the temporary register getting overwritten by the second pair. So
make the code more explicit.

Tested-by: Glenn Kennard <glenn.kennard@gmail.com>
Tested-by: James Harvey <lothmordor@gmail.com>
Cc: 17.0 <mesa-stable@lists.freedesktop.org>
(cherry picked from commit 76b02d2fe1)
This commit is contained in:
Nicolai Hähnle 2017-01-19 14:38:54 +01:00 committed by Emil Velikov
parent 8857256214
commit 41b93b1fe0

View file

@ -4326,25 +4326,27 @@ static int cayman_mul_double_instr(struct r600_shader_ctx *ctx)
int lasti = tgsi_last_instruction(inst->Dst[0].Register.WriteMask);
int t1 = ctx->temp_reg;
for (k = 0; k < 2; k++) {
if (!(inst->Dst[0].Register.WriteMask & (0x3 << (k * 2))))
continue;
/* t1 would get overwritten below if we actually tried to
* multiply two pairs of doubles at a time. */
assert(inst->Dst[0].Register.WriteMask == TGSI_WRITEMASK_XY ||
inst->Dst[0].Register.WriteMask == TGSI_WRITEMASK_ZW);
for (i = 0; i < 4; i++) {
memset(&alu, 0, sizeof(struct r600_bytecode_alu));
alu.op = ctx->inst_info->op;
for (j = 0; j < inst->Instruction.NumSrcRegs; j++) {
r600_bytecode_src(&alu.src[j], &ctx->src[j], k * 2 + ((i == 3) ? 0 : 1));
}
alu.dst.sel = t1;
alu.dst.chan = i;
alu.dst.write = 1;
if (i == 3)
alu.last = 1;
r = r600_bytecode_add_alu(ctx->bc, &alu);
if (r)
return r;
k = inst->Dst[0].Register.WriteMask == TGSI_WRITEMASK_XY ? 0 : 1;
for (i = 0; i < 4; i++) {
memset(&alu, 0, sizeof(struct r600_bytecode_alu));
alu.op = ctx->inst_info->op;
for (j = 0; j < inst->Instruction.NumSrcRegs; j++) {
r600_bytecode_src(&alu.src[j], &ctx->src[j], k * 2 + ((i == 3) ? 0 : 1));
}
alu.dst.sel = t1;
alu.dst.chan = i;
alu.dst.write = 1;
if (i == 3)
alu.last = 1;
r = r600_bytecode_add_alu(ctx->bc, &alu);
if (r)
return r;
}
for (i = 0; i <= lasti; i++) {