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Stop asserting that we're not using the dummy lock implementation

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That implementation no longer exists, so neither 0xABCDEF nor 0xABCDEF2
has any special meaning any more.

Bug: https://bugs.freedesktop.org/show_bug.cgi?id=54972
Signed-off-by: Simon McVittie <simon.mcvittie@collabora.co.uk>
Reviewed-by: Alban Crequy <alban.crequy@collabora.co.uk>
This commit is contained in:
Simon McVittie 2013-05-08 16:58:08 +01:00
parent f541722f5a
commit 2e4d069ac4
1 changed files with 0 additions and 10 deletions
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10
test/name-test/test-threads-init.c
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@ -149,16 +149,6 @@ main (int argc, char *argv[])
&dispatch_cond1,
&io_path_cond1);
/* Since 1.7 it is no longer the case that mutex1 != mutex2, because
* initializing global locks automatically initializes locks
* in general. However, it is true that the mutex is not the dummy
* implementation, which is what we really wanted to check here. */
_dbus_assert (mutex1 != (DBusMutex *) 0xABCDEF);
_dbus_assert (dispatch_mutex1 != (DBusMutex *) 0xABCDEF);
_dbus_assert (dispatch_cond1 != (DBusCondVar *) 0xABCDEF2);
_dbus_assert (io_path_mutex1 != (DBusMutex *) 0xABCDEF);
_dbus_assert (io_path_cond1 != (DBusCondVar *) 0xABCDEF2);
_run_iteration (conn);
_dbus_connection_test_get_locks (conn, &mutex2,
&dispatch_mutex2,